Difference between revisions of "Hazardous Objects"
From Worms Knowledge Base
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* You can make an array with values from 35 to 250 only. If E < 31, E already equals to the value (if E = 5 for example, then C = 5 - considering C is the object count). If E >= 31, then remove 31 to get your array entry and select this entry (for example, 32 - 31 = 1, and 1 is the second value of the array, 1 => 40 so C = 40). | * You can make an array with values from 35 to 250 only. If E < 31, E already equals to the value (if E = 5 for example, then C = 5 - considering C is the object count). If E >= 31, then remove 31 to get your array entry and select this entry (for example, 32 - 31 = 1, and 1 is the second value of the array, 1 => 40 so C = 40). | ||
| − | The array's values are, as we said above | + | The array's values are, as we said above: |
| + | |||
| + | 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190, 200, 210, 220, 230, 240, 250. | ||
'''For example''' | '''For example''' | ||
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* 17 - 1 = 16. Get the entry number 16 of the array. It contains 17. C = 17. | * 17 - 1 = 16. Get the entry number 16 of the array. It contains 17. C = 17. | ||
* 17 < 31, so simply C = E = 17. | * 17 < 31, so simply C = E = 17. | ||
| + | |||
| + | '''Another example''' | ||
| + | |||
| + | V = 246. | ||
| + | |||
| + | As we said above, M = 2. | ||
| + | |||
| + | So: | ||
| + | |||
| + | N = 246 - (8 + 2)<br /> | ||
| + | N = 246 - 10<br /> | ||
| + | N = 236. | ||
| + | |||
| + | Then let's calculate E: | ||
| + | |||
| + | E = 236 / 4<br /> | ||
| + | E = 59. | ||
| + | |||
| + | Then let's see with the 3 methods we suggested for the array: | ||
| + | |||
| + | * Get the 59th entry of the array. Value of it is 250. C = 250. | ||
| + | * 59 - 1 = 58. Get the entry number 58 of the array. It contains 250. C = 250. | ||
| + | * 59 > 31, so 59 - 31 = 28. Entry number 28's value is 250. C = 250. | ||
Revision as of 13:22, 8 October 2011
The Hazardous Objects are the Mines and the Oil Drums (or Barrels).
Contents
Object Types
There can be four values : no objects, mines only, oil drums only, or both objects.
Object Count
This value only exists in W:A. You can set how many objects can appear, from 1 to 250. For having zero objects, simply set "no objects" as the type.
Not all values from 1 to 250 are represented. The following is a breakdown of possible values:
1-30 (1 by 1), 35-100 (5 by 5), 110-250 (10 by 10).
How is this setting saved in a WSC file?
Old schemes
In WWP and W:A v1 schemes (and probably W:A v2 old schemes), only the hazardous object types value is saved.
The values are: 0x00=No objects, 0x01=Mines, 0x02=Oil Drums, 0x05=Both.
New schemes
In new W:A schemes, there is the setting Object Count. So both Oject Types and Count values are stored in the same byte.
Object Types
You have to modulo (%) the value by 4.
- If you get 0, there are no objects.
- If you get 1, there are only mines.
- If you get 2, there are only oil drums.
- If you get 3, there are both objects.
For example :
You have the value "79".
79 % 4 = 3 (because 79 / 4 = 19 and the remainder is 3)
So there will be both mines and oil drums in the scheme.
Another example
You have the value "254".
254 % 4 = 2 (because 254 / 4 = 63 and the remainder is 2)
Object Count
First, you will have to re-use the modulo's result as M.
Then, considering V as the byte's value, do :
N = V - (8 + M)
Then finally, divide N by 4 for getting the array's entry (E).
E = N / 4.
Adjust the E value with your array. Meaning for example:
- You can make an array with a NULL entry as the entry number 0, and you keep the same values for the entries.
- You can make an array normally, meaning you will have to remove 1 to E.
- You can make an array with values from 35 to 250 only. If E < 31, E already equals to the value (if E = 5 for example, then C = 5 - considering C is the object count). If E >= 31, then remove 31 to get your array entry and select this entry (for example, 32 - 31 = 1, and 1 is the second value of the array, 1 => 40 so C = 40).
The array's values are, as we said above:
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190, 200, 210, 220, 230, 240, 250.
For example
We have again the value "79". V = 79.
M = 3 as we saw above.
So:
N = 79 - (8 + 3)
N = 79 - 11
N = 68.
Then let's calculate E:
E = 68 / 4
E = 17.
Then let's see with the 3 methods we suggested for the array:
- Get the 17th entry of the array. Value of it is 17. C = 17.
- 17 - 1 = 16. Get the entry number 16 of the array. It contains 17. C = 17.
- 17 < 31, so simply C = E = 17.
Another example
V = 246.
As we said above, M = 2.
So:
N = 246 - (8 + 2)
N = 246 - 10
N = 236.
Then let's calculate E:
E = 236 / 4
E = 59.
Then let's see with the 3 methods we suggested for the array:
- Get the 59th entry of the array. Value of it is 250. C = 250.
- 59 - 1 = 58. Get the entry number 58 of the array. It contains 250. C = 250.
- 59 > 31, so 59 - 31 = 28. Entry number 28's value is 250. C = 250.
